The alkane that can be oxidized to the corresponding alcohol by $\mathrm{KMnO}_4$ as per the equation is,…

The alkane that can be oxidized to the corresponding alcohol by $\mathrm{KMnO}_4$ as per the equation
is, when:

1. $\mathrm{R}_1=\mathrm{H} ; \mathrm{R}_2=\mathrm{H} ; \mathrm{R}_3=\mathrm{H}$
2. $\mathrm{R}_1=\mathrm{CH}_3 ; \mathrm{R}_2=\mathrm{CH}_3 ; \mathrm{R}_3=\mathrm{CH}_3$
3. $\mathrm{R}_1=\mathrm{CH}_3 ; \mathrm{R} 2=\mathrm{H} ; \mathrm{R}_3=\mathrm{H}$
4. $\mathrm{R}_1=\mathrm{CH}_3 ; \mathrm{R}_2=\mathrm{CH}_3 ; \mathrm{R}_3=\mathrm{H}$

Solution

Generally alkanes resist oxidation but alkane with tertiary H atom(s) can be oxidised to corresponding alcohols by $\mathrm{KMnO}_4$
$\therefore \mathrm{R}_1 \Rightarrow \mathrm{CH}_3 \quad \mathrm{R}_2 \Rightarrow \mathrm{CH}_3 \quad \mathrm{R}_3 \Rightarrow \mathrm{CH}_3$

Asked in: NEET 2024 (Re-NEET)

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