The adsorption of a gas at the boiling point of the gas follows the isotherm shown in the figure. Identify…
The adsorption of a gas at the boiling point of the gas follows the isotherm shown in the figure. Identify the correct thermodynamic properties at point $C$.
$\Delta H=T \Delta S, \Delta G=0$
$\Delta H>T \Delta S, \Delta G=+$ ve
$\Delta H < T \Delta S, \Delta G=-v e$
$\Delta H=T \Delta S=\Delta G=0$
Solution
Amount of gas adsorbed remains constant at point $C$ irrespective of increase in pressure.
So, the system is in equilibrium
$
\therefore \quad \Delta G=0
$
As we know,
$
\Delta G=\Delta H-T \Delta S
$
$
\therefore \quad \Delta H=T \Delta S .
$
