The additon of dilute NaOH to Cr 3 + salt solution will give :

The additon of dilute

NaOH

to

{Cr}^{3 +}

salt solution will give :

a solution of ${[Cr (OH)_{4}]}^{-}$
precipitate of ${[Cr (OH)_{6}]}^{3 -}$
precipitate of ${Cr}_{2} O_{3} {(H_{2} O)}_{n}$
precipitate of $Cr (OH)_{3}$

Solution

{Cr}^{3 +} \overset{dil . NaOH}{⟶} \underset{(Green ppt .)}{{Cr}_{2} O_{3} . (H_{2} O)_{n} ↓}

Asked in: JEE Main 2021 (27 Aug Shift 2)

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