The acute angle between the lines $x-y=0$, and $y=0$ is
The acute angle between the lines $x-y=0$, and $y=0$ is
- $\frac{\pi}{6}$
- $\frac{\pi}{4}$
- $\frac{\pi}{3}$
- $\frac{5 \pi}{6}$
Solution
Equation of given lines $x-y=0$ and $y=0$.
$
\begin{aligned}
\theta & =\cos ^{-1}\left(\frac{|1 \times 0-1 \times 1+0 \times 0|}{\sqrt{1+1} \sqrt{1}}\right) \\
& =\cos ^{-1}\left(\frac{1}{\sqrt{2}}\right)=\frac{\pi}{4}
\end{aligned}
$
Asked in: AP EAMCET 2020 (22 Sep Shift 1)
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