The actual value of resistance R , shown in the figure is 30 Ω . This is measured in an experiment as…

The actual value of resistance R , shown in the figure is 30Ω. This is measured in an experiment as shown using the standard formula R=VI , where V and I are the readings of the voltmeter and ammeter, respectively. If the measured value of R is 5% less, then the internal resistance of the voltmeter is:

  1. 35Ω
  2. 600Ω
  3. 570Ω
  4. 350Ω

Solution

Measured value of R=5% less than
actual value of R i.e., R'=30-(5% of 30)=30-5100×30

R'=28.5 Ω ...i

Now, let us assume that internal resistance of voltmeter RV. Replacing voltmeter with its internal resistance, we get following circuit.

It is clear that the measured value, R' should be equal to parallel combination of R and RV. Mathematically,
R'=R×RVR+RV=28.5 Ω

Given. R=30 Ω

 30 RV30+RV=28.5

 30 RV=28.5×30+28.5 RV

 1.5 RV=28.5×30

 RV=28.5×301.5=19×30

or RV=570 Ω

Asked in: JEE Main 2019 (10 Jan Shift 2)

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