The $\mathrm{Zn}$ acts as sacrificial or cathodic protection to prevent rusting of iron because :
- $\mathrm{E}_{\mathrm{OP}}^{\circ}$ of $\mathrm{Zn} < \mathrm{E}_{\mathrm{OP}}^{\circ}$ of $\mathrm{Fe}$
- $\mathrm{E}_{\mathrm{OP}}^{\circ}$ of $\mathrm{Zn}>\mathrm{E}_{\mathrm{OP}}^{\circ}$ of $\mathrm{Fe}$
- $\mathrm{E}_{\mathrm{OP}}^{\circ}$ of $\mathrm{Zn}=\mathrm{E}_{\mathrm{OP}}^{\circ}$ of $\mathrm{Fe}$
- $\mathrm{Zn}$ is cheaper than iron
Solution
Asked in: JEE-TOPICTESTS-CHEMISTRY