The activation energy of a reaction can be determined from the slope of which of the following graphs?

The activation energy of a reaction can be determined from the slope of which of the following graphs?

$l n K v s . T$
$\frac{l n K}{T} v s . T$
$l n K v s . \frac{1}{T}$
$\frac{T}{(\ln K)} vs . \frac{1}{T}$

Solution

As per Arrhenius equation

K = A e^{- \frac{E a}{R T}}

ln

K =

In

A - \frac{E a}{R T}

Plot of ln

K v/s \frac{1}{T}

will give

Slope = - \frac{E a}{R}

∴ E_{a} = - R (s l o p e)

Asked in: NEET 2015 (Phase 1)

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