The activation energy for a simple chemical reaction $\mathrm{A} ightarrow \mathrm{B}$ is $E_{a}$ in forward…
- is always double of $E_{a}$
- is negative of $E_{a}$
- is always less than $E_{a}$
- can be less than or more than $E_{a}$
Solution
As $\Delta \mathrm{H}=E_{a}$ (forward reaction) $-E_{a}$
(backward reaction)
For exothermic reaction
$\Delta \mathrm{H}=-\mathrm{ve}$
$\therefore-\Delta \mathrm{H}=E_{a}(\mathrm{f})-E_{a}(\mathrm{~b})$
or $E_{a}(\mathrm{f})=E_{a}(\mathrm{~b})-\Delta \mathrm{H}$
$\therefore E_{a}(\mathrm{f}) < E_{a}(\mathrm{~b})$
for endothermic reaction
$\Delta \mathrm{H}=+\mathrm{ve}$
$\therefore \Delta \mathrm{H}=E_{a}(\mathrm{f})-E_{a}(\mathrm{~b})$ or $E_{a}(\mathrm{f})=\Delta \mathrm{H}+E_{a}(\mathrm{~b})$
$\therefore E_{a}(\mathrm{f})>E_{a}(\mathrm{~b})$ *
Asked in: JEE-TOPICTESTS-CHEMISTRY