The acceleration of a particle executing SHM is

The acceleration of a particle executing SHM is
  1. always zero
  2. always constant
  3. maximum at the extreme position
  4. maximum at the equilibrium position

Solution

The acceleration of the particle executing SHM is given as $ \alpha=-\omega^2 y \Rightarrow \alpha \propto y $ Since, maximum value of displacement $y$ from mean position is equal to amplitude $a$. Hence, acceleration of a particle executing SHM is maximum at extreme position

Asked in: AP EAMCET 2020 (22 Sep Shift 1)

Practice more Oscillations questions on Aicharya