The acceleration of a body sliding down the inclined plane, having coefficient of friction ' $\mu$ ', is

The acceleration of a body sliding down the inclined plane, having coefficient of friction ' $\mu$ ', is
  1. $a=g(\sin \theta+\mu \cos \theta$
  2. $a=g(\sin \theta-\mu \cos \theta)$
  3. $a=g(\cos \theta-\mu \sin \theta)$
  4. $a=g(\cos \theta+\mu \sin \theta)$

Solution


The acceleration of the body down the inclined plane is $\begin{aligned} & a=\frac{F_{\text {net }}}{M}=\frac{(m g \sin \theta-\mu m g \cos \theta)}{m} \\ & =g(\sin \theta-\mu \cos \theta) \end{aligned}$

Asked in: AP EAMCET 2024 (22 May Shift 2)

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