The acceleration at the end of 2   s , of a particle whose motion is represented by the equation S = 4…

The acceleration at the end of 2 s, of a particle whose motion is represented by the equation S=4t3-8t2+5t+4 is ______
  1. 32 m s-2
  2. 40 m s-2
  3. 37 m s-2
  4. 35 m s-2

Solution

Given that 

displacement S=4t3-8t2+5t+4

velocity 

v=dSdt

⇒v=d4t3-8t2+5t+4dt

⇒v=12t2-16t+5

acceleration

a=dvdt

⇒a=d12t2-16t+5dt

⇒a=24t-16

so acceleration at t=2 

a=242-16=32 m s-2

Asked in: AP EAMCET 2020 (23 Sep Shift 1)

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