The abscissa of the point on the curve…

The abscissa of the point on the curve $y=\mathrm{a}\left(\mathrm{e}^{\frac{x}{a}}+\mathrm{e}^{-\frac{x}{a}}\right)$ where the tangent is parallel to the X -axis is
  1. 0
  2. a
  3. 2 a
  4. -2 a

Solution

$\begin{aligned} & \quad y=\mathrm{a}\left(\mathrm{e}^{\frac{x}{a}}+\mathrm{e}^{\frac{-x}{a}}\right) \\ & \therefore \quad \frac{\mathrm{d} y}{\mathrm{~d} x}=\mathrm{e}^{\frac{x}{a}}-\mathrm{e}^{-\frac{x}{a}} \end{aligned}$
Since the tangent is parallel to X -axis, $\frac{\mathrm{d} y}{\mathrm{~d} x}=0$ $\begin{aligned} & \Rightarrow \mathrm{e}^{\frac{x}{\mathrm{a}}}-\mathrm{e}^{-\frac{x}{\mathrm{a}}}=0 \\ & \Rightarrow \mathrm{e}^{\frac{2 x}{\mathrm{a}}}=0 \\ & \Rightarrow x=0 \end{aligned}$

Asked in: MHT CET 2024 (16 May Shift 1)

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