Temporary hardness of water is removed in Clark's process by adding

Temporary hardness of water is removed in Clark's process by adding
  1. caustic soda
  2. calgon
  3. borax
  4. lime

Solution

The temporary hardness of water is due to the presence of bicarbonates of $\mathrm{Ca}$ and $\mathrm{Mg}$. This may be removed by Clark's process. In this process, addition of calculated quantity of lime causes precipitation of $\mathrm{CaCO}_3$ as $ \begin{array}{r} \mathrm{Ca}\left(\mathrm{HCO}_3\right)_2+\mathrm{Ca}(\mathrm{OH})_2 \longrightarrow 2 \mathrm{CaCO}_3 \downarrow+2 \mathrm{H}_2 \mathrm{O} \\ \text { and } \mathrm{Mg}\left(\mathrm{HCO}_3\right)_2+2 \mathrm{Ca}(\mathrm{OH})_2 \underset{2}{\longrightarrow} 2 \mathrm{CaCO}_3 \downarrow \\ +\mathrm{Mg}(\mathrm{OH})_2+2 \mathrm{H}_2 \mathrm{O} \end{array} $

Asked in: AP EAMCET 2014

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