temperature of $27^\circ\text{C}$, two successive resonances are produced at $20\text{ cm}$ and $73\text{…

temperature of $27^\circ\text{C}$, two successive resonances are produced at $20\text{ cm}$ and $73\text{ cm}$ of column length. If the frequency of the tuning fork is $320\text{ Hz}$, the velocity of sound in air at $27^\circ\text{C}$ is [NEET 2018]
  1. (a) $350\text{ ms}^{-1}$
  2. (b) $339\text{ ms}^{-1}$
  3. (c) $330\text{ ms}^{-1}$
  4. (d) $300\text{ ms}^{-1}$

Solution

For first resonance, $l_1 = \frac{\lambda}{4}$ For second resonance, $l_2 = \frac{3\lambda}{4}$ $\therefore (l_2 - l_1) = \frac{3\lambda}{4} - \frac{\lambda}{4}$ or $\lambda = 2(l_2 - l_1)$ ...(i) As, velocity of sound wave is given as $v = \nu\lambda$ where, $\nu$ is the frequency. $\Rightarrow v = \nu[2(l_2 - l_1)]$ ...(ii) [From Eq. (i)] Here, $\nu = 320\text{ Hz}$, $l_2 = 0.73\text{ m}$, $l_1 = 0.20\text{ m}$ (Given) Putting the values in Eq. (ii), we get $v = 320[2(0.73 - 0.20)] = 2 \times 320 \times 0.53$ $= 339.2\text{ ms}^{-1} \simeq 339\text{ ms}^{-1}$

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