Temperature of cold junction in a thermocouple is $10^{\circ} \mathrm{C}$ and neutral temperature is…
Temperature of cold junction in a thermocouple is $10^{\circ} \mathrm{C}$ and neutral temperature is $270^{\circ} \mathrm{C}$, then the temperature of inversion is
$540^{\circ} \mathrm{C}$
$530^{\circ} \mathrm{C}$
$280^{\circ} \mathrm{C}$
$260^{\circ} \mathrm{C}$
Solution
Temperature of inversion is
$\begin{aligned} & T_i=2 T_n-T_0 \\ & \therefore \quad T_i=2 \times 270-10=530^{\circ} \mathrm{C} \\ & \end{aligned}$