Taking earth to be a metallic sphere, its capacity will approximately be
Taking earth to be a metallic sphere, its capacity will approximately be
- \(6.4 \times 10^6 \mathrm{~F}\)
- \(700 \mathrm{~F}\)
- \(700 \mu \mathrm{F}\)
- \(700 \mathrm{pF}\)
Solution
Radius of earth, \(R=6400 \mathrm{~km}=6.4 \times 10^6 \mathrm{~m}\)
Taking earth to be a metallic sphere, its capacitance is given as
\(\begin{aligned}
C & =4 \pi \varepsilon_0 R=\frac{1}{9 \times 10^9} \times 6.4 \times 10^6 \\
& =0.7111 \times 10^{-3} \mathrm{~F}=711.1 \times 10^{-6} \mathrm{~F} \\
& =711 \mu \mathrm{F}=700 \mu \mathrm{F}
\end{aligned}\)
Asked in: AP EAMCET 2020 (21 Sep Shift 2)
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