Suppose refractive index $\mu$ is given as $\mu=A+\frac{B}{\lambda^{2}}$ where $A$ and $B$ are constants and $\lambda$ is wavelength, then dimensions of $B$ are same as that of

Question

Aicharya · Accepted Answer

As $\mu=\frac{\text { velocity of light in vaceum }}{\text { velocity of light in medium }}$ hence, $\mu$ is dimensionless. Thus, each term on the R.H.S. of given equation should be dimensionless, i.e., $\frac{B}{\lambda^{2}}$ is dimensionless, i.e., $B$ should have dimension of $\lambda^{2}$, i.e., $\mathrm{cm}^{2}$, i.e., area.

Suppose refractive index \(\mu\) is given as \(\mu=A+\frac{B}{\lambda^{2}}\) where \(A\) and \(B\) are…

Solution