Suppose $A$ is any $3 \times 3$ non-singular matrix and $(A-3 I)(A-5 I)=O$, where $I=I_3$ and $O=O_3$. If…

Suppose $A$ is any $3 \times 3$ non-singular matrix and $(A-3 I)(A-5 I)=O$, where $I=I_3$ and $O=O_3$. If $\alpha A+$ $\beta A^{-1}=4 I$, then $\alpha+\beta$ is equal to
  1. 8
  2. 12
  3. 13
  4. 7

Solution

We have $ \begin{aligned} &(A-3 I)(A-5 I)=O \\ &\Rightarrow A^2-8 A+15 I=O \end{aligned} $ Multiplying both sides by $A^{-1}$, we get; $ \begin{aligned} A^{-1} A \cdot A-8 A^{-1} A+15 A^{-1} I=A^{-1} O \\ \Rightarrow & A-8 I+15 A^{-1}=O \\ & A+15 A^{-1}=8 I \\ & \frac{A}{2}+\frac{15 A^{-1}}{2}=4 I \\ \therefore & \alpha+\beta=\frac{1}{2}+\frac{15}{2}=\frac{16}{2}=8 \end{aligned} $

Asked in: JEE Main 2018 (15 Apr Shift 2 Online)

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