Suppose $A$ and $B$ are two events such that $P(A \cap B)=\frac{3}{25}$ and $P(B-A)=\frac{8}{25} . \quad$…

Suppose $A$ and $B$ are two events such that $P(A \cap B)=\frac{3}{25}$ and $P(B-A)=\frac{8}{25} . \quad$ Then, $P(B)$ is equal to
  1. $\frac{11}{25}$
  2. $\frac{3}{11}$
  3. $\frac{1}{11}$
  4. $\frac{9}{11}$

Solution


Given, $P(A \cap B)=\frac{3}{25}$ $P(B-A)=\frac{8}{25}$ Then according to figure $P(B)=P(A \cap B)+P(B-A)$ $P(B)=\frac{3}{25}+\frac{8}{25} \quad \Rightarrow \quad P(B)=\frac{11}{25}$

Asked in: AP EAMCET 2010

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