Sum of two rationals is $\dfrac{7}{12}$ and one is $\dfrac{1}{3}$. The other is

Sum of two rationals is $\dfrac{7}{12}$ and one is $\dfrac{1}{3}$. The other is
  1. $\dfrac{1}{4}$
  2. $\dfrac{1}{2}$
  3. $\dfrac{3}{4}$
  4. $\dfrac{2}{12}$

Solution

$\dfrac{7}{12} - \dfrac{4}{12} = \dfrac{3}{12} = \dfrac{1}{4}$.

Asked in: IMO

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