Sum of three consecutive even integers is $48$. The middle is

Sum of three consecutive even integers is $48$. The middle is
  1. $16$
  2. $14$
  3. $18$
  4. $12$

Solution

$(x-2) + x + (x+2) = 48 \Rightarrow 3x = 48 \Rightarrow x = 16$.

Asked in: IMO

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