Sum of the roots of the equation $$ \left|\begin{array}{cccc} x & 0 & 0 & 0 \\ 0 & 0 & 0 & 1 \\ 0 & x & 0 &…

Sum of the roots of the equation $$ \left|\begin{array}{cccc} x & 0 & 0 & 0 \\ 0 & 0 & 0 & 1 \\ 0 & x & 0 & 0 \\ 2 & 0 & x-1 & 0 \end{array}\right|-\left|\begin{array}{ccc} 0 & x & 0 \\ 0 & 0 & x-1 \\ 2 & 2 & 0 \end{array}\right|=0 \mathrm{is} $$
  1. 2
  2. 3
  3. 1
  4. 5

Solution

$\left|\begin{array}{cccc}x & 0 & 0 & 0 \\ 0 & 0 & 0 & 1 \\ 0 & x & 0 & 0 \\ 2 & 0 & x-1 & 0\end{array}\right|-\left|\begin{array}{ccc}0 & x & 0 \\ 0 & 0 & x-1 \\ 2 & 2 & 0\end{array}\right|=0$ On expanding first determinant along $R_2$ and second determinant along $R_i$ $ \begin{aligned} & 1\left[x^2(x-1)\right]-(-x)[-2(x-1)]=0 \\ & x^3-x^2+x(-2 x+2)=0 \\ & x^3-x^2-2 x^2+2 x=0 \\ & x^3-3 x^2+2 x=0 \\ & x\left(x^2-3 x+2\right)=0 \\ & x(x-1)(x-2)=0 \\ & x=0,1 \text { and } 2 \\ & \Rightarrow \quad \end{aligned} $ $x=0,1$ and 2 $\therefore$ Sum of the roots $=0+1+2=3$

Asked in: AP EAMCET 2021 (25 Aug Shift 2)

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