Sum of the roots of the equation $$ \left|\begin{array}{cccc} x & 0 & 0 & 0 \\ 0 & 0 & 0 & 1 \\ 0 & x & 0 &…
Sum of the roots of the equation
$$
\left|\begin{array}{cccc}
x & 0 & 0 & 0 \\
0 & 0 & 0 & 1 \\
0 & x & 0 & 0 \\
2 & 0 & x-1 & 0
\end{array}\right|-\left|\begin{array}{ccc}
0 & x & 0 \\
0 & 0 & x-1 \\
2 & 2 & 0
\end{array}\right|=0 \mathrm{is}
$$
- 2
- 3
- 1
- 5
Solution
$\left|\begin{array}{cccc}x & 0 & 0 & 0 \\ 0 & 0 & 0 & 1 \\ 0 & x & 0 & 0 \\ 2 & 0 & x-1 & 0\end{array}\right|-\left|\begin{array}{ccc}0 & x & 0 \\ 0 & 0 & x-1 \\ 2 & 2 & 0\end{array}\right|=0$
On expanding first determinant along $R_2$ and second determinant along $R_i$
$
\begin{aligned}
& 1\left[x^2(x-1)\right]-(-x)[-2(x-1)]=0 \\
& x^3-x^2+x(-2 x+2)=0 \\
& x^3-x^2-2 x^2+2 x=0 \\
& x^3-3 x^2+2 x=0 \\
& x\left(x^2-3 x+2\right)=0 \\
& x(x-1)(x-2)=0 \\
& x=0,1 \text { and } 2 \\
& \Rightarrow \quad
\end{aligned}
$
$x=0,1$ and 2
$\therefore$ Sum of the roots $=0+1+2=3$
Asked in: AP EAMCET 2021 (25 Aug Shift 2)
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