Sum of squares of two numbers is $61$ and their product is $30$. Find $(a + b)^{2}$.

Sum of squares of two numbers is $61$ and their product is $30$. Find $(a + b)^{2}$.
  1. $121$
  2. $91$
  3. $81$
  4. $100$

Solution

$(a+b)^{2} = a^{2}+b^{2}+2ab = 61 + 60 = 121$.

Asked in: IMO

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