Sum of present ages of three brothers is $36$. Their ages are in ratio $2:3:4$. Age of eldest is

Sum of present ages of three brothers is $36$. Their ages are in ratio $2:3:4$. Age of eldest is
  1. $16$
  2. $12$
  3. $8$
  4. $18$

Solution

$2k+3k+4k=9k=36 \Rightarrow k=4$. Eldest $= 16$.

Asked in: IMO

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