Sum of additive inverse of $\dfrac{5}{6}$ and multiplicative inverse of $\dfrac{5}{6}$ is

Sum of additive inverse of $\dfrac{5}{6}$ and multiplicative inverse of $\dfrac{5}{6}$ is
  1. $\dfrac{11}{30}$
  2. $0$
  3. $1$
  4. $-\dfrac{1}{30}$

Solution

$-\dfrac{5}{6} + \dfrac{6}{5} = \dfrac{-25+36}{30} = \dfrac{11}{30}$.

Asked in: IMO

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