Sulphur trioxide is dissolved in heavy water to form a compound $X$. The hybridisation state of sulphur in…
Sulphur trioxide is dissolved in heavy water to form a compound $X$. The hybridisation state of sulphur in $X$ is :
$s p^2$
$s p^3$
$s p$
$d s p^2$
Solution
When $\mathrm{SO}_3$ is dissolved in heavy water $\mathrm{D}_2 \mathrm{SO}_4$ is formed as
$\mathrm{SO}_3+\mathrm{D}_2 \mathrm{O} \longrightarrow \underset{(X)}{\mathrm{D}_2 \mathrm{SO}_4}$
The hybridisation state of $\mathrm{S}$ in $\mathrm{D}_2 \mathrm{SO}_4$ is $s p^3$