Suitable conditions to prepare hexachlorobenzene from benzene is/are

1. \(\mathrm{Cl}_2\) (excess), anhyd. \(\mathrm{AlCl}_3\), dark, cold
2. \(\mathrm{Cl}_2\) (excess), anhyd. \(\mathrm{AlCl}_3, \Delta\)
3. \(\mathrm{Cl}_2\) (excess), anhyd. \(\mathrm{ZnCl}_2, \Delta\)
4. \(\mathrm{Cl}_2\) (excess), UV, \(500 \mathrm{~K}\)

Solution

It is a free radical addition reaction.

Asked in: AP EAMCET 2020 (17 Sep Shift 2)

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