Sucrose is a non-reducing sugar due to
- 1-2 linkage
- 1-4 linkage
- $1-5$ linkage
- 1-6 linkage
Solution

Therefore, there is no free aldehyde or ketone group (reducing of group) as they are involved in glycosidic linkage.
Asked in: MHT CET Full Test 10

Asked in: MHT CET Full Test 10