Substance $\mathrm{A}_{2} \mathrm{~B}(\mathrm{~g})$ can undergoes decomposition to form two set of products…

Substance $\mathrm{A}_{2} \mathrm{~B}(\mathrm{~g})$ can undergoes decomposition to form two set of products :
$A_{2} B(g) \longrightarrow \quad \begin{array}{l}\longrightarrow A_{2}(g)+B(g) ; \Delta H^{\circ}=40 \mathrm{~kJ} / \mathrm{mol} \\ \longrightarrow A(g)+A B(g) ; \Delta H^{\circ}=50 \mathrm{~kJ} / \mathrm{mol}\end{array}$
If the molar ratio of $\mathrm{A}_{2}(\mathrm{~g})$ to $\mathrm{A}(\mathrm{g})$ is $5: 3$ in a set of product gases, then the energy involved in the decomposition of 1 mole of $\mathrm{A}_{2} \mathrm{~B}(\mathrm{~g})$ is :
  1. $48.75 \mathrm{~kJ} / \mathrm{mol}$
  2. $43.75 \mathrm{~kJ} / \mathrm{mol}$
  3. $46.25 \mathrm{~kJ} / \mathrm{mol}$
  4. None of these

Solution

$\Delta_{\mathrm{r}} \mathrm{H}=\frac{5}{8} \times 40+\frac{3}{8} \times 50=43.75 \mathrm{~kJ} / \mathrm{mol}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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