Styrene on reaction with reagent X gave Y which on hydrolysis followed by oxidation gave Z . Z gives…

Styrene on reaction with reagent X gave Y which on hydrolysis followed by oxidation gave Z . Z gives positive 2,4 - DNP test but does not give iodoform test. What are X and Z respectively?

$\mathrm{HBr} ; \mathrm{C}_6 \mathrm{H}_5 \mathrm{CO} \mathrm{CH}_3$
$\mathrm{HBr} ; \mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{CHO}$
$\mathrm{HBr} /\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{CO}\right)_2 \mathrm{O}_2 ; \mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{CHO}$
$\mathrm{HBr} /\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{CO}\right)_2 \mathrm{O}_2 ; \mathrm{C}_6 \mathrm{H}_5 \mathrm{CO} \mathrm{CH}_3$

Solution

2, 4- DNP test given by both aldehyde and ketones

So a and d option eliminated.

Asked in: AP EAMCET 2024 (20 May Shift 2)

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