Statement I The number of ways of distributing 10 identical balls in 4 distinct boxes such that no box is…

Statement I The number of ways of distributing 10 identical balls in 4 distinct boxes such that no box is empty is ${ }^9 C_3$. Statement II The number of ways of choosing 3 places from 9 different places is ${ }^9 \mathrm{C}_3$.
  1. Statement I is true, statement II is true, statement II is not a correct explanation for statement I
  2. Statement I is true, statement II is false
  3. Statement I is false, statement II is true
  4. Statement I is true, statement II is true, statement II is a correct explanation for statement I

Solution

Statement I The number of ways of distributing 10 identical balls in 4 distinct boxes such that no box is empty is ${ }^9 C_3$. $\because n$ identical things can be distributed to different boxes by ${ }^{t-1} C_{r-1}$ ways such that no box is empty. 10 identical balls can be distributed to 4 distinct boxes by ${ }^{10-1} C_{4-1}$ ways i.e. ${ }^9 C_3$ ways Statement II The number of ways of choosing 3 places from 9 different places is ${ }^9 C_3$ (true) $\therefore$ Statement I is true statement II is true, statement II is not a correct explanation for statement I.

Asked in: AP EAMCET 2021 (24 Aug Shift 1)

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