Statement-1 : Two particles moving in the same direction do not lose all their energy in a completely…
- Statement-1 is true, Statement-2 is true; Statement-2 is the correct explanation of Statement-1.
- Statement-1 is true, Statement-2 is true; Statement-2 is not the correct explanation of Statement1
- Statement-1 is false, Statement-2 is true.
- Statement-1 is true, Statement-2 is false.
Solution

If it is a completely inelastic collision then $ \begin{gathered} m_1 v_1+m_2 v_2=m_1 v+m_2 v \\ v=\frac{m_1 v_1+m_2 v_2}{m_1+m_2} \\ \mathrm{~K} \cdot \mathrm{E}=\frac{\mathrm{p}_1^2}{2 \mathrm{~m}_1}+\frac{\mathrm{p}_2^2}{2 \mathrm{~m}_2} \end{gathered} $ as $\overrightarrow{\mathrm{p}}_1$ and $\overrightarrow{\mathrm{p}_2}$ both simultaneously cannot be zero therefore total KE cannot be lost
Asked in: JEE Main 2010
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