Starting from the origin at time t = 0 , with initial velocity 5   j ⏜   ms − 1 , a…

Starting from the origin at time t=0, with initial velocity 5 j⏜ ms−1, a particle moves in the x -y plane with a constant acceleration of 10i⏜+4j⏜ms−2. At time t, its coordinates are 20 m, y0 m. The values of t and y0 are, respectively:
  1. 2 s and 18 m
  2. 4 s and 52 m
  3. 2 s and 24 m
  4. 5 s and 25 m

Solution

Equation 1

Sx=12axt2

20=12×10×t2

t=2

Equation 2

Sy=uyt+12ayt2

y=52+12422

y=18

Asked in: JEE Main 2020 (04 Sep Shift 1)

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