Starting at temperature 300 K , one mole of an ideal diatomic gas γ = 1.4 is first compressed adiabatically from volume V 1 to V 2 = V 1 16 . It is then allowed to expand isobarically to volume 2 V 2 . If all the processes are the quasi-static then the final temperature of the gas (in o K )…

Question

Starting at temperature 300 K , one mole of an ideal diatomic gas &#947; = 1.4 is first compressed adiabatically from volume V 1 to V 2 = V 1 16 . It is then allowed to expand isobarically to volume 2 V 2 . If all the processes are the quasi-static then the final temperature of the gas (in o K ) is (to the nearest integer) ___________.

Aicharya · Accepted Answer

P V y = c o n s t a n t T V - 1 = c o n s t a n t 300 V 1 1.4 - 1 = T B V 1 16 2 / 5 T B = 300 × 2 8 / 5 Now for BC process V B T B = V c T c T c = V c T B v B = 2 × 300 × 2 8 / 5 T c = 1818.859 T c = 1819 K

Starting at temperature 300 K , one mole of an ideal diatomic gas γ = 1.4 is first compressed…

Solution

Starting at temperature 300 K , one mole of an ideal diatomic gas &#947; = 1.4 is first compressed…

Solution

Starting at temperature 300 K , one mole of an ideal diatomic gas γ = 1.4 is first compressed…