Standing waves are produced in $10 ext{ m}$ long stretched string. If the string vibrates in 5 segments and wave velocity is $20 ext{ ms}^{-1}$, then its frequency will be

Question

Standing waves are produced in $10	ext{ m}$ long stretched string. If the string vibrates in 5 segments and wave velocity is $20	ext{ ms}^{-1}$, then its frequency will be

Aicharya · Accepted Answer

Five segments means five loops. Length of one loop is $\frac{\lambda}{2}$. Hence, $5 \frac{\lambda}{2} = 10	ext{ m}$ $	herefore \lambda = 4	ext{ m}$ Now, frequency, $f = \frac{v}{\lambda} = 5	ext{ Hz}$

Standing waves are produced in $10\text{ m}$ long stretched string. If the string vibrates in 5 segments and…

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