Standard electrode potential of three metals $X, Y$ and $Z$ are $-1.2 \mathrm{~V},+0.5 \mathrm{~V}$ and $-3…
Standard electrode potential of three metals $X, Y$ and $Z$ are $-1.2 \mathrm{~V},+0.5 \mathrm{~V}$ and $-3.0 \mathrm{~V}$ respectively. The reducing power of these metals will be
$Y > X > Z$
$Z > X > Y$
$X > Y > Z$
$Y > Z > X$
Solution
$\begin{aligned}
& E_X^{\circ}=-1.2 \mathrm{~V} \\
& E_Y^{\circ}=+0.5 \mathrm{~V} \\
& E_Z^{\circ}=-3.0 \mathrm{~V} \\
& \therefore Z > X > Y[\because \text { higher the reduction potential, lesser the reducing power.}
\end{aligned}$