Spin only magnetic moment 2 .84 BM is given by: (Atomic Number of Ni =28, Ti =22, Cr =24, Co =27 )

Spin only magnetic moment 2.84 BM is given by:
(Atomic Number of Ni=28,Ti=22,Cr=24,Co=27)
  1. Ni2+
  2. Ti3+
  3. Cr2+
  4. Co2+

Solution

μ= n( n+2 ) =2.84⇒n=2
electronic configuration of Ni +2 =1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 3 d 8   e − having two unpaired electrons
electron configuration of T i 3+ =1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 3 d 1 only one unpaired electron
electron configuration of C r 2+ =1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 3 d 4 having four unpaired electrons
electron configuration of C o +2 =1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 3 d 7 having three unpaired electrons.

Asked in: MHT CET Full Test 3

Practice more Transition and Inner Transition Elements questions on Aicharya