Some amount of dichloromethane CH 2 Cl 2 is added to 671 . 141 mL of chloroform CHCl 3 to prepare 2 . 6…

Some amount of dichloromethane CH2Cl2 is added to 671.141mL of chloroform CHCl3 to prepare 2.6×10-3M solution of CH2Cl2DCM. The concentration of DCM is _____ ppm (by mass).

Given: Atomic mass : C=12;H:1;Cl=35.5 density of CHCl3=1.49g cm-3

Solution

Molarity= mole  Volume in L =mass/Molar massVolume in L

2.6×10-3=x/850.67141

x=0.148 g

The number of ppm =mass of solutemass of solution×106

Mass of solution = density of solution×Volume of solution

 DCM in ppm =0.1481.49×671.141×106

=148ppm.

Asked in: JEE Main 2023 (30 Jan Shift 1)

Practice more Solutions questions on Aicharya