Solve: i x 2 - 3 x - 2 i = 0

Solve: ix2-3x-2i=0
  1. -i only
  2. -2i only
  3. -i and -2i
  4. i only

Solution

Given, ix2-3x-2i=0

⇒ix2+3i2x-2i=0

⇒ix2+i2x+2i2x+2i3=0

⇒ix(x+i)+2i2(x+i)=0

⇒(x+i)(x+2i)=0

⇒x=-i, -2i.

Asked in: AP EAMCET 2020 (23 Sep Shift 1)

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