Solve $\left(\dfrac{1}{2}\right)^{x} = 64$.

Solve $\left(\dfrac{1}{2}\right)^{x} = 64$.
  1. $6$
  2. $-6$
  3. $-8$
  4. $\dfrac{1}{6}$

Solution

$64 = 2^{6} = \left(\dfrac{1}{2}\right)^{-6}$, so $x = -6$.

Asked in: IMO

Practice more EXPONENTS AND POWERS questions on Aicharya