Solve $\dfrac{x - 5}{x + 5} = \dfrac{1}{3}$.

Solve $\dfrac{x - 5}{x + 5} = \dfrac{1}{3}$.
  1. $10$
  2. $5$
  3. $-10$
  4. $15$

Solution

$3(x - 5) = x + 5 \Rightarrow 2x = 20 \Rightarrow x = 10$.

Asked in: IMO

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