Solve $\dfrac{x - 3}{2x + 1} = \dfrac{2}{5}$.

Solve $\dfrac{x - 3}{2x + 1} = \dfrac{2}{5}$.
  1. $17$
  2. $\dfrac{17}{9}$
  3. $5$
  4. $3$

Solution

$5(x-3) = 2(2x+1) \Rightarrow 5x - 15 = 4x + 2 \Rightarrow x = 17$.

Asked in: IMO

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