Solve $\dfrac{x - 2}{3} = \dfrac{x + 1}{4}$.

Solve $\dfrac{x - 2}{3} = \dfrac{x + 1}{4}$.
  1. $11$
  2. $5$
  3. $7$
  4. $3$

Solution

$4(x-2) = 3(x+1) \Rightarrow 4x - 8 = 3x + 3 \Rightarrow x = 11$.

Asked in: IMO

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