Solve $\dfrac{x + 1}{x - 1} = 3$.

Solve $\dfrac{x + 1}{x - 1} = 3$.
  1. $2$
  2. $1$
  3. $-2$
  4. $\dfrac{4}{3}$

Solution

$x + 1 = 3x - 3 \Rightarrow 4 = 2x \Rightarrow x = 2$.

Asked in: IMO

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