Solve $\dfrac{4x + 3}{5x - 7} = \dfrac{2}{3}$.

Solve $\dfrac{4x + 3}{5x - 7} = \dfrac{2}{3}$.
  1. $-\dfrac{23}{2}$
  2. $\dfrac{23}{2}$
  3. $5$
  4. $2$

Solution

$3(4x + 3) = 2(5x - 7) \Rightarrow 12x + 9 = 10x - 14 \Rightarrow 2x = -23 \Rightarrow x = -\dfrac{23}{2}$.

Asked in: IMO

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