Solve $\dfrac{3}{x - 1} = \dfrac{2}{x + 1}$.

Solve $\dfrac{3}{x - 1} = \dfrac{2}{x + 1}$.
  1. $-5$
  2. $5$
  3. $1$
  4. $0$

Solution

$3(x+1) = 2(x-1) \Rightarrow 3x + 3 = 2x - 2 \Rightarrow x = -5$.

Asked in: IMO

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