Solve $\dfrac{2x - 3}{4x + 1} = \dfrac{1}{3}$.

Solve $\dfrac{2x - 3}{4x + 1} = \dfrac{1}{3}$.
  1. $5$
  2. $2$
  3. $3$
  4. $1$

Solution

$3(2x - 3) = 4x + 1 \Rightarrow 6x - 9 = 4x + 1 \Rightarrow x = 5$.

Asked in: IMO

Practice more LINEAR EQUATIONS IN ONE VARIABLE questions on Aicharya