Solve $\dfrac{2x + 1}{3x - 1} = \dfrac{3}{4}$.

Solve $\dfrac{2x + 1}{3x - 1} = \dfrac{3}{4}$.
  1. $7$
  2. $5$
  3. $2$
  4. $3$

Solution

$4(2x+1) = 3(3x-1) \Rightarrow 8x + 4 = 9x - 3 \Rightarrow x = 7$.

Asked in: IMO

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