Solve $7^{x} = \dfrac{1}{49}$.

Solve $7^{x} = \dfrac{1}{49}$.
  1. $2$
  2. $-2$
  3. $\dfrac{1}{2}$
  4. $-\dfrac{1}{2}$

Solution

$\dfrac{1}{49} = 7^{-2}$, so $x = -2$.

Asked in: NSO

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