Solve $4^{x} = 8^{x-1}$.

Solve $4^{x} = 8^{x-1}$.
  1. $1$
  2. $2$
  3. $3$
  4. $4$

Solution

Base 2: $(2^{2})^{x} = (2^{3})^{x-1} \Rightarrow 2x = 3x - 3 \Rightarrow x = 3$.

Asked in: IMO

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